13001031121031 has 4 divisors (see below), whose sum is σ = 13045403241192. Its totient is φ = 12956659000872.

The previous prime is 13001031120997. The next prime is 13001031121063. The reversal of 13001031121031 is 13012113010031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001031121031 - 2¹⁴ = 13001031104647 is a prime.

It is a super-3 number, since 3×13001031121031³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001031121081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22186059641 + ... + 22186060226.

It is an arithmetic number, because the mean of its divisors is an integer number (3261350810298).

Almost surely, 2^{13001031121031} is an apocalyptic number.

13001031121031 is a deficient number, since it is larger than the sum of its proper divisors (44372120161).

13001031121031 is an equidigital number, since it uses as much as digits as its factorization.

13001031121031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44372120160.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13001031121031 its reverse (13012113010031), we get a palindrome (26013144131062).

The spelling of 13001031121031 in words is "thirteen trillion, one billion, thirty-one million, one hundred twenty-one thousand, thirty-one".