Base | Representation |
---|---|
bin | 111100100010100110… |
… | …1111110101010001111 |
3 | 110102120122100010002020 |
4 | 1321011031332222033 |
5 | 4112230114430221 |
6 | 135420444101223 |
7 | 12251530261326 |
oct | 1710515765217 |
9 | 412518303066 |
10 | 130010311311 |
11 | 50156482181 |
12 | 21244234813 |
13 | c34c074cba |
14 | 64149d10bd |
15 | 35adbedac6 |
hex | 1e4537ea8f |
130010311311 has 16 divisors (see below), whose sum is σ = 173938332768. Its totient is φ = 86378342400.
The previous prime is 130010311309. The next prime is 130010311351. The reversal of 130010311311 is 113113010031.
It is not a de Polignac number, because 130010311311 - 21 = 130010311309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130010311351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1181271 + ... + 1286631.
It is an arithmetic number, because the mean of its divisors is an integer number (10871145798).
Almost surely, 2130010311311 is an apocalyptic number.
130010311311 is a deficient number, since it is larger than the sum of its proper divisors (43928021457).
130010311311 is a wasteful number, since it uses less digits than its factorization.
130010311311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106762.
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 130010311311 its reverse (113113010031), we get a palindrome (243123321342).
It can be divided in two parts, 1300 and 10311311, that added together give a triangular number (10312611 = T4541).
The spelling of 130010311311 in words is "one hundred thirty billion, ten million, three hundred eleven thousand, three hundred eleven".
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