Base | Representation |
---|---|
bin | 11101100011111001100011… |
… | …101010000001011010010101 |
3 | 122001022212101120111210011210 |
4 | 131203321203222001122111 |
5 | 114020042124443311013 |
6 | 1140301531052452033 |
7 | 36245636140303131 |
oct | 3543714352013225 |
9 | 561285346453153 |
10 | 130010332010133 |
11 | 3847508806a383 |
12 | 126b8a5917a019 |
13 | 5770bc9c9a353 |
14 | 24167684683c1 |
15 | 1006d01689cc3 |
hex | 763e63a81695 |
130010332010133 has 4 divisors (see below), whose sum is σ = 173347109346848. Its totient is φ = 86673554673420.
The previous prime is 130010332010107. The next prime is 130010332010179. The reversal of 130010332010133 is 331010233010031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 130010332010133 - 241 = 127811308754581 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130010322010133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21668388668353 + ... + 21668388668358.
It is an arithmetic number, because the mean of its divisors is an integer number (43336777336712).
Almost surely, 2130010332010133 is an apocalyptic number.
It is an amenable number.
130010332010133 is a deficient number, since it is larger than the sum of its proper divisors (43336777336715).
130010332010133 is an equidigital number, since it uses as much as digits as its factorization.
130010332010133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43336777336714.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 130010332010133 its reverse (331010233010031), we get a palindrome (461020565020164).
The spelling of 130010332010133 in words is "one hundred thirty trillion, ten billion, three hundred thirty-two million, ten thousand, one hundred thirty-three".
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