1300104421031 has 4 divisors (see below), whose sum is σ = 1400112453432. Its totient is φ = 1200096388632.

The previous prime is 1300104421009. The next prime is 1300104421037. The reversal of 1300104421031 is 1301244010031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300104421031 - 2³⁰ = 1299030679207 is a prime.

It is a super-2 number, since 2×1300104421031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300104420994 and 1300104421012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300104421037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50004016181 + ... + 50004016206.

It is an arithmetic number, because the mean of its divisors is an integer number (350028113358).

Almost surely, 2^{1300104421031} is an apocalyptic number.

1300104421031 is a deficient number, since it is larger than the sum of its proper divisors (100008032401).

1300104421031 is a wasteful number, since it uses less digits than its factorization.

1300104421031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100008032400.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1300104421031 its reverse (1301244010031), we get a palindrome (2601348431062).

The spelling of 1300104421031 in words is "one trillion, three hundred billion, one hundred four million, four hundred twenty-one thousand, thirty-one".