Base | Representation |
---|---|
bin | 11101100011111010001101… |
… | …011100001010111000101011 |
3 | 122001022221012102120212200002 |
4 | 131203322031130022320223 |
5 | 114020100043423200440 |
6 | 1140302124413533215 |
7 | 36245662411640366 |
oct | 3543721534127053 |
9 | 561287172525602 |
10 | 130011033021995 |
11 | 3847540783aa24 |
12 | 126b9013aa420b |
13 | 5770cac2a2178 |
14 | 24167d35c70dd |
15 | 1006d42eac115 |
hex | 763e8d70ae2b |
130011033021995 has 16 divisors (see below), whose sum is σ = 156968942164320. Its totient is φ = 103373282246400.
The previous prime is 130011033021983. The next prime is 130011033022009. The reversal of 130011033021995 is 599120330110031.
It is not a de Polignac number, because 130011033021995 - 240 = 128911521394219 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 98774186 + ... + 100081775.
It is an arithmetic number, because the mean of its divisors is an integer number (9810558885270).
Almost surely, 2130011033021995 is an apocalyptic number.
130011033021995 is a deficient number, since it is larger than the sum of its proper divisors (26957909142325).
130011033021995 is a wasteful number, since it uses less digits than its factorization.
130011033021995 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198856766.
The product of its (nonzero) digits is 21870, while the sum is 38.
The spelling of 130011033021995 in words is "one hundred thirty trillion, eleven billion, thirty-three million, twenty-one thousand, nine hundred ninety-five".
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