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1300112120011 = 4996872601853
BaseRepresentation
bin10010111010110100101…
…110001001100011001011
311121021211001022201222011
4102322310232021203023
5132300112200320021
62433132510440351
7162633663453025
oct22726456114313
94537731281864
101300112120011
11461413441661
1218bb78b030b7
13957a53c2743
1446cd6413015
1523c43bc0de1
hex12eb4b898cb

1300112120011 has 4 divisors (see below), whose sum is σ = 1300115221552. Its totient is φ = 1300109018472.

The previous prime is 1300112119991. The next prime is 1300112120071. The reversal of 1300112120011 is 1100212110031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300112120011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300112119973 and 1300112120000.

It is not an unprimeable number, because it can be changed into a prime (1300112120071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 801240 + ... + 1800613.

It is an arithmetic number, because the mean of its divisors is an integer number (325028805388).

Almost surely, 21300112120011 is an apocalyptic number.

1300112120011 is a deficient number, since it is larger than the sum of its proper divisors (3101541).

1300112120011 is an equidigital number, since it uses as much as digits as its factorization.

1300112120011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3101540.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1300112120011 its reverse (1100212110031), we get a palindrome (2400324230042).

The spelling of 1300112120011 in words is "one trillion, three hundred billion, one hundred twelve million, one hundred twenty thousand, eleven".

Divisors: 1 499687 2601853 1300112120011