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1300113033311 = 3137414444703
BaseRepresentation
bin10010111010110100110…
…001101000100001011111
311121021211010001010210002
4102322310301220201133
5132300112414031221
62433132542204515
7162634004305511
oct22726461504137
94537733033702
101300113033311
11461413a05854
1218bb7928373b
13957a5652361
1446cd65adbb1
1523c43d0180b
hex12eb4c6885f

1300113033311 has 4 divisors (see below), whose sum is σ = 1300527481152. Its totient is φ = 1299698585472.

The previous prime is 1300113033287. The next prime is 1300113033337. The reversal of 1300113033311 is 1133303110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300113033311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300113063311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207219215 + ... + 207225488.

It is an arithmetic number, because the mean of its divisors is an integer number (325131870288).

Almost surely, 21300113033311 is an apocalyptic number.

1300113033311 is a deficient number, since it is larger than the sum of its proper divisors (414447841).

1300113033311 is an equidigital number, since it uses as much as digits as its factorization.

1300113033311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 414447840.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 1300113033311 its reverse (1133303110031), we get a palindrome (2433416143342).

The spelling of 1300113033311 in words is "one trillion, three hundred billion, one hundred thirteen million, thirty-three thousand, three hundred eleven".

Divisors: 1 3137 414444703 1300113033311