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13001132311 = 45832836817
BaseRepresentation
bin11000001101110110…
…11000100100010111
31020120001220221200221
430012323120210113
5203111242213221
65550031215211
7640115541556
oct140673304427
936501827627
1013001132311
115571889152
12262a077507
1312c26aa1cb
148b4981d9d
155115c7541
hex306ed8917

13001132311 has 4 divisors (see below), whose sum is σ = 13003973712. Its totient is φ = 12998290912.

The previous prime is 13001132297. The next prime is 13001132321. The reversal of 13001132311 is 11323110031.

13001132311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001132311 - 223 = 12992743703 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001132321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1413826 + ... + 1422991.

It is an arithmetic number, because the mean of its divisors is an integer number (3250993428).

Almost surely, 213001132311 is an apocalyptic number.

13001132311 is a deficient number, since it is larger than the sum of its proper divisors (2841401).

13001132311 is an equidigital number, since it uses as much as digits as its factorization.

13001132311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2841400.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13001132311 its reverse (11323110031), we get a palindrome (24324242342).

The spelling of 13001132311 in words is "thirteen billion, one million, one hundred thirty-two thousand, three hundred eleven".

Divisors: 1 4583 2836817 13001132311