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1300113303 = 3433371101
BaseRepresentation
bin100110101111110…
…0010011110010111
310100121101121011120
41031133202132113
510130312111203
6333001535023
744134531536
oct11537423627
93317347146
101300113303
11607975405
123034a4473
13179477718
14c495031d
1579213b53
hex4d7e2797

1300113303 has 4 divisors (see below), whose sum is σ = 1733484408. Its totient is φ = 866742200.

The previous prime is 1300113293. The next prime is 1300113307. The reversal of 1300113303 is 3033110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300113303 - 25 = 1300113271 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300113307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216685548 + ... + 216685553.

It is an arithmetic number, because the mean of its divisors is an integer number (433371102).

Almost surely, 21300113303 is an apocalyptic number.

1300113303 is a deficient number, since it is larger than the sum of its proper divisors (433371105).

1300113303 is an equidigital number, since it uses as much as digits as its factorization.

1300113303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433371104.

The product of its (nonzero) digits is 81, while the sum is 15.

The square root of 1300113303 is about 36057.0839503141. The cubic root of 1300113303 is about 1091.4245893420.

Adding to 1300113303 its reverse (3033110031), we get a palindrome (4333223334).

The spelling of 1300113303 in words is "one billion, three hundred million, one hundred thirteen thousand, three hundred three".

Divisors: 1 3 433371101 1300113303