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13001133302203 = 61213133332823
BaseRepresentation
bin1011110100110000111111…
…1011101010000110111011
31201000220012100000020122011
42331030033323222012323
53201002310111132303
643352345503110351
72511205126455424
oct275141773520673
951026170006564
1013001133302203
1141628278a0492
12155b8592a23b7
137340036c9137
1432d38875264b
151782c8dea16d
hexbd30feea1bb

13001133302203 has 4 divisors (see below), whose sum is σ = 13214266635088. Its totient is φ = 12787999969320.

The previous prime is 13001133302167. The next prime is 13001133302279. The reversal of 13001133302203 is 30220333110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13001133302203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001133302303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106566666351 + ... + 106566666472.

It is an arithmetic number, because the mean of its divisors is an integer number (3303566658772).

Almost surely, 213001133302203 is an apocalyptic number.

13001133302203 is a deficient number, since it is larger than the sum of its proper divisors (213133332885).

13001133302203 is an equidigital number, since it uses as much as digits as its factorization.

13001133302203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213133332884.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13001133302203 its reverse (30220333110031), we get a palindrome (43221466412234).

The spelling of 13001133302203 in words is "thirteen trillion, one billion, one hundred thirty-three million, three hundred two thousand, two hundred three".

Divisors: 1 61 213133332823 13001133302203