Base | Representation |
---|---|
bin | 10010111010110100110… |
… | …101100001010100000001 |
3 | 11121021211011221220122101 |
4 | 102322310311201110001 |
5 | 132300113144133403 |
6 | 2433133020110401 |
7 | 162634016051464 |
oct | 22726465412401 |
9 | 4537734856571 |
10 | 1300114052353 |
11 | 461414541436 |
12 | 18bb79695401 |
13 | 957a591b13c |
14 | 46cd67972db |
15 | 23c43e5371d |
hex | 12eb4d61501 |
1300114052353 has 16 divisors (see below), whose sum is σ = 1370216675520. Its totient is φ = 1230179844096.
The previous prime is 1300114052333. The next prime is 1300114052371. The reversal of 1300114052353 is 3532504110031.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-1300114052353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300114052333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65728801 + ... + 65748577.
It is an arithmetic number, because the mean of its divisors is an integer number (85638542220).
Almost surely, 21300114052353 is an apocalyptic number.
It is an amenable number.
1300114052353 is a deficient number, since it is larger than the sum of its proper divisors (70102623167).
1300114052353 is a wasteful number, since it uses less digits than its factorization.
1300114052353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23856.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1300114052353 its reverse (3532504110031), we get a palindrome (4832618162384).
The spelling of 1300114052353 in words is "one trillion, three hundred billion, one hundred fourteen million, fifty-two thousand, three hundred fifty-three".
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