Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0011101011000110010 |
3 | 110102120202112102021220 |
4 | 1321011110131120302 |
5 | 4112231033310114 |
6 | 135420544325510 |
7 | 12251550565014 |
oct | 1710524353062 |
9 | 412522472256 |
10 | 130012010034 |
11 | 50157432485 |
12 | 21244913896 |
13 | c34c51b26a |
14 | 6414d141b4 |
15 | 35ade370a9 |
hex | 1e4551d632 |
130012010034 has 16 divisors (see below), whose sum is σ = 263315464320. Its totient is φ = 42788762640.
The previous prime is 130012009999. The next prime is 130012010123. The reversal of 130012010034 is 430010210031.
It is a junction number, because it is equal to n+sod(n) for n = 130012009995 and 130012010022.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 137142997 + ... + 137143944.
It is an arithmetic number, because the mean of its divisors is an integer number (16457216520).
Almost surely, 2130012010034 is an apocalyptic number.
130012010034 is an abundant number, since it is smaller than the sum of its proper divisors (133303454286).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130012010034 is a wasteful number, since it uses less digits than its factorization.
130012010034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274287025.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 130012010034 its reverse (430010210031), we get a palindrome (560022220065).
The spelling of 130012010034 in words is "one hundred thirty billion, twelve million, ten thousand, thirty-four".
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