Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0100101000011011010 |
3 | 110102120202121000100212 |
4 | 1321011110211003122 |
5 | 4112231040311214 |
6 | 135420545131122 |
7 | 12251551055402 |
oct | 1710524450332 |
9 | 412522530325 |
10 | 130012041434 |
11 | 50157454030 |
12 | 21244929aa2 |
13 | c34c52c642 |
14 | 6414d21802 |
15 | 35ade4153e |
hex | 1e455250da |
130012041434 has 16 divisors (see below), whose sum is σ = 212942018016. Its totient is φ = 59042204400.
The previous prime is 130012041433. The next prime is 130012041463. The reversal of 130012041434 is 434140210031.
It is a super-2 number, since 2×1300120414342 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (130012041433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2684357 + ... + 2732360.
It is an arithmetic number, because the mean of its divisors is an integer number (13308876126).
Almost surely, 2130012041434 is an apocalyptic number.
130012041434 is a deficient number, since it is larger than the sum of its proper divisors (82929976582).
130012041434 is a wasteful number, since it uses less digits than its factorization.
130012041434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5417821.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 130012041434 its reverse (434140210031), we get a palindrome (564152251465).
The spelling of 130012041434 in words is "one hundred thirty billion, twelve million, forty-one thousand, four hundred thirty-four".
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