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13001210431 = 111315989819
BaseRepresentation
bin11000001101110111…
…01011101000111111
31020120002001220212021
430012323223220333
5203111302213211
65550033021011
7640116315406
oct140673535077
936502056767
1013001210431
115571931910
12262a0b4767
1312c2706931
148b49a263d
155115e0771
hex306eeba3f

13001210431 has 8 divisors (see below), whose sum is σ = 14184374400. Its totient is φ = 11818252440.

The previous prime is 13001210423. The next prime is 13001210473. The reversal of 13001210431 is 13401210031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13001210431 - 23 = 13001210423 is a prime.

It is a super-2 number, since 2×130012104312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001210491) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99840 + ... + 189658.

It is an arithmetic number, because the mean of its divisors is an integer number (1773046800).

Almost surely, 213001210431 is an apocalyptic number.

13001210431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13001210431 is a deficient number, since it is larger than the sum of its proper divisors (1183163969).

13001210431 is a wasteful number, since it uses less digits than its factorization.

13001210431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102989.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13001210431 its reverse (13401210031), we get a palindrome (26402420462).

The spelling of 13001210431 in words is "thirteen billion, one million, two hundred ten thousand, four hundred thirty-one".

Divisors: 1 11 13159 89819 144749 988009 1181928221 13001210431