Search a number
-
+
130012113103 = 177647771359
BaseRepresentation
bin111100100010101010…
…0110110100011001111
3110102120202201122200021
41321011110312203033
54112231100104403
6135420550443011
712251551504345
oct1710524664317
9412522648607
10130012113103
11501574a2964
1221244963467
13c34c556152
146414d3d995
1535ade578bd
hex1e455368cf

130012113103 has 4 divisors (see below), whose sum is σ = 137659884480. Its totient is φ = 122364341728.

The previous prime is 130012113097. The next prime is 130012113221. The reversal of 130012113103 is 301311210031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130012113103 - 25 = 130012113071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130012114103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3823885663 + ... + 3823885696.

It is an arithmetic number, because the mean of its divisors is an integer number (34414971120).

Almost surely, 2130012113103 is an apocalyptic number.

130012113103 is a deficient number, since it is larger than the sum of its proper divisors (7647771377).

130012113103 is an equidigital number, since it uses as much as digits as its factorization.

130012113103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7647771376.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130012113103 its reverse (301311210031), we get a palindrome (431323323134).

The spelling of 130012113103 in words is "one hundred thirty billion, twelve million, one hundred thirteen thousand, one hundred three".

Divisors: 1 17 7647771359 130012113103