Base | Representation |
---|---|
bin | 111100100010101010… |
… | …1011011000101010010 |
3 | 110102120210000020221022 |
4 | 1321011111123011102 |
5 | 4112231114401423 |
6 | 135420553555442 |
7 | 12251552666531 |
oct | 1710525330522 |
9 | 412523006838 |
10 | 130012262738 |
11 | 50157595326 |
12 | 21244a15b82 |
13 | c34c5a92a7 |
14 | 6414d7c318 |
15 | 35ade86dc8 |
hex | 1e4555b152 |
130012262738 has 6 divisors (see below), whose sum is σ = 195019158999. Its totient is φ = 65005876406.
The previous prime is 130012262701. The next prime is 130012262747. The reversal of 130012262738 is 837262210031.
It can be written as a sum of positive squares in only one way, i.e., 65006131369 + 65006131369 = 254963^2 + 254963^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=254963.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130012262698 and 130012262707.
It is an unprimeable number.
It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 382445 + ... + 637407.
Almost surely, 2130012262738 is an apocalyptic number.
130012262738 is a deficient number, since it is larger than the sum of its proper divisors (65006896261).
130012262738 is an frugal number, since it uses more digits than its factorization.
130012262738 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 509928 (or 254965 counting only the distinct ones).
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 130012262738 its reverse (837262210031), we get a palindrome (967274472769).
The spelling of 130012262738 in words is "one hundred thirty billion, twelve million, two hundred sixty-two thousand, seven hundred thirty-eight".
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