Base | Representation |
---|---|
bin | 10010111010110101011… |
… | …000100010000000001101 |
3 | 11121021211211020012022102 |
4 | 102322311120202000031 |
5 | 132300123021331341 |
6 | 2433133544524445 |
7 | 162634160055224 |
oct | 22726530420015 |
9 | 4537754205272 |
10 | 1300123230221 |
11 | 46141973a952 |
12 | 18bb80780725 |
13 | 957a77b272a |
14 | 46cd7aa5cbb |
15 | 23c44b67c9b |
hex | 12eb562200d |
1300123230221 has 4 divisors (see below), whose sum is σ = 1300153912092. Its totient is φ = 1300092548352.
The previous prime is 1300123230193. The next prime is 1300123230223. The reversal of 1300123230221 is 1220323210031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 595388164996 + 704735065225 = 771614^2 + 839485^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300123230221 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1300123230193 and 1300123230202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300123230223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15277286 + ... + 15362151.
It is an arithmetic number, because the mean of its divisors is an integer number (325038478023).
Almost surely, 21300123230221 is an apocalyptic number.
It is an amenable number.
1300123230221 is a deficient number, since it is larger than the sum of its proper divisors (30681871).
1300123230221 is an equidigital number, since it uses as much as digits as its factorization.
1300123230221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30681870.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1300123230221 its reverse (1220323210031), we get a palindrome (2520446440252).
The spelling of 1300123230221 in words is "one trillion, three hundred billion, one hundred twenty-three million, two hundred thirty thousand, two hundred twenty-one".
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