130013104114 has 4 divisors (see below), whose sum is σ = 195019656174. Its totient is φ = 65006552056.

The previous prime is 130013104093. The next prime is 130013104127. The reversal of 130013104114 is 411401310031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 79928902089 + 50084202025 = 282717^2 + 223795^2 .

It is a super-3 number, since 3×130013104114³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130013104091 and 130013104100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32503276027 + ... + 32503276030.

Almost surely, 2^130013104114 is an apocalyptic number.

130013104114 is a deficient number, since it is larger than the sum of its proper divisors (65006552060).

130013104114 is an equidigital number, since it uses as much as digits as its factorization.

130013104114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65006552059.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 130013104114 its reverse (411401310031), we get a palindrome (541414414145).

The spelling of 130013104114 in words is "one hundred thirty billion, thirteen million, one hundred four thousand, one hundred fourteen".