13001311301333 has 4 divisors (see below), whose sum is σ = 13002591094080. Its totient is φ = 13000031508588.

The previous prime is 13001311301263. The next prime is 13001311301339. The reversal of 13001311301333 is 33310311310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001311301333 - 2¹² = 13001311297237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13001311301299 and 13001311301308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001311301339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 639881135 + ... + 639901452.

It is an arithmetic number, because the mean of its divisors is an integer number (3250647773520).

Almost surely, 2^{13001311301333} is an apocalyptic number.

It is an amenable number.

13001311301333 is a deficient number, since it is larger than the sum of its proper divisors (1279792747).

13001311301333 is a wasteful number, since it uses less digits than its factorization.

13001311301333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1279792746.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 13001311301333 its reverse (33310311310031), we get a palindrome (46311622611364).

The spelling of 13001311301333 in words is "thirteen trillion, one billion, three hundred eleven million, three hundred one thousand, three hundred thirty-three".