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13001320013 = 111181938183
BaseRepresentation
bin11000001101111000…
…00110011001001101
31020120002021111011212
430012330012121031
5203111314220023
65550035224205
7640120253033
oct140674063115
936502244155
1013001320013
1155719a7180
12262a148065
1312c2744786
148b49d0553
15511612e78
hex306f0664d

13001320013 has 4 divisors (see below), whose sum is σ = 14183258208. Its totient is φ = 11819381820.

The previous prime is 13001320001. The next prime is 13001320021. The reversal of 13001320013 is 31002310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001320013 - 26 = 13001319949 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13001320013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001320093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590969081 + ... + 590969102.

It is an arithmetic number, because the mean of its divisors is an integer number (3545814552).

Almost surely, 213001320013 is an apocalyptic number.

It is an amenable number.

13001320013 is a deficient number, since it is larger than the sum of its proper divisors (1181938195).

13001320013 is a wasteful number, since it uses less digits than its factorization.

13001320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1181938194.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13001320013 its reverse (31002310031), we get a palindrome (44003630044).

The spelling of 13001320013 in words is "thirteen billion, one million, three hundred twenty thousand, thirteen".

Divisors: 1 11 1181938183 13001320013