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130013210023 = 4115391206033
BaseRepresentation
bin111100100010101100…
…1000010010110100111
3110102120211210101100221
41321011121002112213
54112231340210043
6135421030145211
712251564023354
oct1710531022647
9412524711327
10130013210023
1150158082004
12212451b2207
13c34c84b508
14641514762b
1535ae0c28ed
hex1e456425a7

130013210023 has 8 divisors (see below), whose sum is σ = 133193563776. Its totient is φ = 126833299200.

The previous prime is 130013209993. The next prime is 130013210087. The reversal of 130013210023 is 320012310031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130013210023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130013209979 and 130013210006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130013216023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 528015 + ... + 734047.

It is an arithmetic number, because the mean of its divisors is an integer number (16649195472).

Almost surely, 2130013210023 is an apocalyptic number.

130013210023 is a deficient number, since it is larger than the sum of its proper divisors (3180353753).

130013210023 is a wasteful number, since it uses less digits than its factorization.

130013210023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221465.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 130013210023 its reverse (320012310031), we get a palindrome (450025520054).

The spelling of 130013210023 in words is "one hundred thirty billion, thirteen million, two hundred ten thousand, twenty-three".

Divisors: 1 41 15391 206033 631031 8447353 3171053903 130013210023