130013232211131 has 4 divisors (see below), whose sum is σ = 173350976281512. Its totient is φ = 86675488140752.

The previous prime is 130013232211007. The next prime is 130013232211139. The reversal of 130013232211131 is 131112232310031.

130013232211131 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130013232211131 - 2¹⁵ = 130013232178363 is a prime.

It is a super-2 number, since 2×130013232211131² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130013232211139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21668872035186 + ... + 21668872035191.

It is an arithmetic number, because the mean of its divisors is an integer number (43337744070378).

Almost surely, 2^{130013232211131} is an apocalyptic number.

130013232211131 is a deficient number, since it is larger than the sum of its proper divisors (43337744070381).

130013232211131 is an equidigital number, since it uses as much as digits as its factorization.

130013232211131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43337744070380.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 130013232211131 its reverse (131112232310031), we get a palindrome (261125464521162).

The spelling of 130013232211131 in words is "one hundred thirty trillion, thirteen billion, two hundred thirty-two million, two hundred eleven thousand, one hundred thirty-one".