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130013240353 = 563332307941
BaseRepresentation
bin111100100010101100…
…1001001110000100001
3110102120211211220222021
41321011121021300201
54112231342142403
6135421030541441
712251564210653
oct1710531116041
9412524756867
10130013240353
11501580a2877
1221245207881
13c34c85c269
1464151546d3
1535ae0cb8bd
hex1e45649c21

130013240353 has 4 divisors (see below), whose sum is σ = 130015604628. Its totient is φ = 130010876080.

The previous prime is 130013240341. The next prime is 130013240359. The reversal of 130013240353 is 353042310031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20542915584 + 109470324769 = 143328^2 + 330863^2 .

It is a cyclic number.

It is not a de Polignac number, because 130013240353 - 225 = 129979685921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130013240359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1097638 + ... + 1210303.

It is an arithmetic number, because the mean of its divisors is an integer number (32503901157).

Almost surely, 2130013240353 is an apocalyptic number.

It is an amenable number.

130013240353 is a deficient number, since it is larger than the sum of its proper divisors (2364275).

130013240353 is an equidigital number, since it uses as much as digits as its factorization.

130013240353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2364274.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 130013240353 its reverse (353042310031), we get a palindrome (483055550384).

The spelling of 130013240353 in words is "one hundred thirty billion, thirteen million, two hundred forty thousand, three hundred fifty-three".

Divisors: 1 56333 2307941 130013240353