Search a number
-
+
130013548249 = 1310001042173
BaseRepresentation
bin111100100010101101…
…0010100111011011001
3110102120212102120022211
41321011122110323121
54112231432020444
6135421041315121
712251566632424
oct1710532247331
9412525376284
10130013548249
1150158293132
1221245335aa1
13c34c939450
1464151d49bb
1535ae13cc34
hex1e45694ed9

130013548249 has 4 divisors (see below), whose sum is σ = 140014590436. Its totient is φ = 120012506064.

The previous prime is 130013548219. The next prime is 130013548253. The reversal of 130013548249 is 942845310031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 942845310031 = 4321926635117.

It can be written as a sum of positive squares in 2 ways, for example, as 86932394649 + 43081153600 = 294843^2 + 207560^2 .

It is a cyclic number.

It is not a de Polignac number, because 130013548249 - 215 = 130013515481 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130013548219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000521074 + ... + 5000521099.

It is an arithmetic number, because the mean of its divisors is an integer number (35003647609).

Almost surely, 2130013548249 is an apocalyptic number.

It is an amenable number.

130013548249 is a deficient number, since it is larger than the sum of its proper divisors (10001042187).

130013548249 is a wasteful number, since it uses less digits than its factorization.

130013548249 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10001042186.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 130013548249 in words is "one hundred thirty billion, thirteen million, five hundred forty-eight thousand, two hundred forty-nine".

Divisors: 1 13 10001042173 130013548249