1300140001123 has 4 divisors (see below), whose sum is σ = 1310064734088. Its totient is φ = 1290215268160.

The previous prime is 1300140001093. The next prime is 1300140001159. The reversal of 1300140001123 is 3211000410031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300140001123 - 2²¹ = 1300137903971 is a prime.

It is a super-2 number, since 2×1300140001123² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300140001097 and 1300140001106.

It is not an unprimeable number, because it can be changed into a prime (1300140001163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4962366286 + ... + 4962366547.

It is an arithmetic number, because the mean of its divisors is an integer number (327516183522).

Almost surely, 2^{1300140001123} is an apocalyptic number.

1300140001123 is a deficient number, since it is larger than the sum of its proper divisors (9924732965).

1300140001123 is an equidigital number, since it uses as much as digits as its factorization.

1300140001123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9924732964.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1300140001123 its reverse (3211000410031), we get a palindrome (4511140411154).

The spelling of 1300140001123 in words is "one trillion, three hundred billion, one hundred forty million, one thousand, one hundred twenty-three".