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130014352443 = 343338117481
BaseRepresentation
bin111100100010101110…
…1011001010000111011
3110102120220221102110210
41321011131121100323
54112232133234233
6135421110442203
712251606522133
oct1710535312073
9412526842423
10130014352443
1150158792358
1221245663363
13c34cb5b4c1
146415363ac3
1535ae24b163
hex1e4575943b

130014352443 has 4 divisors (see below), whose sum is σ = 173352469928. Its totient is φ = 86676234960.

The previous prime is 130014352397. The next prime is 130014352541. The reversal of 130014352443 is 344253410031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344253410031 = 3114751136677.

It is not a de Polignac number, because 130014352443 - 218 = 130014090299 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130014352443.

It is not an unprimeable number, because it can be changed into a prime (130014352043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21669058738 + ... + 21669058743.

It is an arithmetic number, because the mean of its divisors is an integer number (43338117482).

Almost surely, 2130014352443 is an apocalyptic number.

130014352443 is a deficient number, since it is larger than the sum of its proper divisors (43338117485).

130014352443 is an equidigital number, since it uses as much as digits as its factorization.

130014352443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43338117484.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 130014352443 its reverse (344253410031), we get a palindrome (474267762474).

The spelling of 130014352443 in words is "one hundred thirty billion, fourteen million, three hundred fifty-two thousand, four hundred forty-three".

Divisors: 1 3 43338117481 130014352443