Base | Representation |
---|---|
bin | 11101100011111101010110… |
… | …101110101111100010011011 |
3 | 122001100020220210011210001111 |
4 | 131203331112232233202123 |
5 | 114020124002442024011 |
6 | 1140303443452401151 |
7 | 36246142166503330 |
oct | 3543752656574233 |
9 | 561306823153044 |
10 | 130014410111131 |
11 | 38476890047a87 |
12 | 126b97b6a761b7 |
13 | 57713c9b35970 |
14 | 2416a33d0c987 |
15 | 1006e8e6db121 |
hex | 763f56baf89b |
130014410111131 has 32 divisors (see below), whose sum is σ = 163745903946240. Its totient is φ = 100472064021504.
The previous prime is 130014410110987. The next prime is 130014410111147. The reversal of 130014410111131 is 131111014410031.
It is a de Polignac number, because none of the positive numbers 2k-130014410111131 is a prime.
It is a super-2 number, since 2×1300144101111312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130014410111731) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 94871211 + ... + 96231883.
It is an arithmetic number, because the mean of its divisors is an integer number (5117059498320).
Almost surely, 2130014410111131 is an apocalyptic number.
130014410111131 is a deficient number, since it is larger than the sum of its proper divisors (33731493835109).
130014410111131 is a wasteful number, since it uses less digits than its factorization.
130014410111131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1385155.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 130014410111131 its reverse (131111014410031), we get a palindrome (261125424521162).
The spelling of 130014410111131 in words is "one hundred thirty trillion, fourteen billion, four hundred ten million, one hundred eleven thousand, one hundred thirty-one".
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