1300164114913 has 4 divisors (see below), whose sum is σ = 1300394115988. Its totient is φ = 1299934113840.

The previous prime is 1300164114877. The next prime is 1300164114919. The reversal of 1300164114913 is 3194114610031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1127434105249 + 172730009664 = 1061807^2 + 415608^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300164114913 - 2¹³ = 1300164106721 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300164114919) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114992058 + ... + 115003363.

It is an arithmetic number, because the mean of its divisors is an integer number (325098528997).

Almost surely, 2^{1300164114913} is an apocalyptic number.

It is an amenable number.

1300164114913 is a deficient number, since it is larger than the sum of its proper divisors (230001075).

1300164114913 is an equidigital number, since it uses as much as digits as its factorization.

1300164114913 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230001074.

The product of its (nonzero) digits is 7776, while the sum is 34.

Adding to 1300164114913 its reverse (3194114610031), we get a palindrome (4494278724944).

The spelling of 1300164114913 in words is "one trillion, three hundred billion, one hundred sixty-four million, one hundred fourteen thousand, nine hundred thirteen".