Base | Representation |
---|---|
bin | 1011110100110011010001… |
… | …0101010100111100000011 |
3 | 1201000221202220011110121220 |
4 | 2331030310111110330003 |
5 | 3201010032431323021 |
6 | 43352530240450123 |
7 | 2511226223425530 |
oct | 275146425247403 |
9 | 51027686143556 |
10 | 13001744011011 |
11 | 41630105a3008 |
12 | 155b9a9919943 |
13 | 7340a00a40b2 |
14 | 32d4058c5d87 |
15 | 178312830cc6 |
hex | bd334554f03 |
13001744011011 has 16 divisors (see below), whose sum is σ = 20854927737600. Its totient is φ = 7038538111008.
The previous prime is 13001744010979. The next prime is 13001744011057. The reversal of 13001744011011 is 11011044710031.
13001744011011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13001744011011 - 25 = 13001744010979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13001744016011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16292911896 + ... + 16292912693.
It is an arithmetic number, because the mean of its divisors is an integer number (1303432983600).
Almost surely, 213001744011011 is an apocalyptic number.
13001744011011 is a deficient number, since it is larger than the sum of its proper divisors (7853183726589).
13001744011011 is a wasteful number, since it uses less digits than its factorization.
13001744011011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32585824618.
The product of its (nonzero) digits is 336, while the sum is 24.
Adding to 13001744011011 its reverse (11011044710031), we get a palindrome (24012788721042).
The spelling of 13001744011011 in words is "thirteen trillion, one billion, seven hundred forty-four million, eleven thousand, eleven".
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