130018413504001 has 4 divisors (see below), whose sum is σ = 141838269277104. Its totient is φ = 118198557730900.

The previous prime is 130018413503981. The next prime is 130018413504017. The reversal of 130018413504001 is 100405314810031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130018413504001 - 2³⁷ = 129880974550529 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130018413504041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5909927886535 + ... + 5909927886556.

It is an arithmetic number, because the mean of its divisors is an integer number (35459567319276).

Almost surely, 2^{130018413504001} is an apocalyptic number.

130018413504001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

130018413504001 is a deficient number, since it is larger than the sum of its proper divisors (11819855773103).

130018413504001 is a wasteful number, since it uses less digits than its factorization.

130018413504001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11819855773102.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 130018413504001 in words is "one hundred thirty trillion, eighteen billion, four hundred thirteen million, five hundred four thousand, one".