Base | Representation |
---|---|
bin | 10010111010111001111… |
… | …101011011001000111111 |
3 | 11121022001011201000210011 |
4 | 102322321331123020333 |
5 | 132300302200312203 |
6 | 2433145330324051 |
7 | 162636111510655 |
oct | 22727175331077 |
9 | 4538034630704 |
10 | 1300200010303 |
11 | 461459011967 |
12 | 18bba2429627 |
13 | 957ba68632c |
14 | 46d03d70dd5 |
15 | 23c4b78276d |
hex | 12eb9f5b23f |
1300200010303 has 4 divisors (see below), whose sum is σ = 1335340551160. Its totient is φ = 1265059469448.
The previous prime is 1300200010289. The next prime is 1300200010309. The reversal of 1300200010303 is 3030100020031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1300200010303 - 221 = 1300197913151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300200010309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17570270373 + ... + 17570270446.
It is an arithmetic number, because the mean of its divisors is an integer number (333835137790).
Almost surely, 21300200010303 is an apocalyptic number.
1300200010303 is a deficient number, since it is larger than the sum of its proper divisors (35140540857).
1300200010303 is an equidigital number, since it uses as much as digits as its factorization.
1300200010303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35140540856.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 1300200010303 its reverse (3030100020031), we get a palindrome (4330300030334).
The spelling of 1300200010303 in words is "one trillion, three hundred billion, two hundred million, ten thousand, three hundred three".
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