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13002002233111 = 19168073310121
BaseRepresentation
bin1011110100110100001110…
…1110010111011100010111
31201000222102220001111202101
42331031003232113130113
53201011100032424421
643353012023222531
72511235510323613
oct275150356273427
951028386044671
1013002002233111
114163133332101
12155ba602a7a47
13734111735038
1432d42bd02343
1517832a33b191
hexbd343b97717

13002002233111 has 4 divisors (see below), whose sum is σ = 13070075543424. Its totient is φ = 12933928922800.

The previous prime is 13002002233069. The next prime is 13002002233117. The reversal of 13002002233111 is 11133220020031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13002002233111 - 27 = 13002002232983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002002233117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34036654870 + ... + 34036655251.

It is an arithmetic number, because the mean of its divisors is an integer number (3267518885856).

Almost surely, 213002002233111 is an apocalyptic number.

13002002233111 is a deficient number, since it is larger than the sum of its proper divisors (68073310313).

13002002233111 is an equidigital number, since it uses as much as digits as its factorization.

13002002233111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68073310312.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13002002233111 its reverse (11133220020031), we get a palindrome (24135222253142).

The spelling of 13002002233111 in words is "thirteen trillion, two billion, two million, two hundred thirty-three thousand, one hundred eleven".

Divisors: 1 191 68073310121 13002002233111