130020224313431 has 4 divisors (see below), whose sum is σ = 130024746312912. Its totient is φ = 130015702313952.

The previous prime is 130020224313359. The next prime is 130020224313439. The reversal of 130020224313431 is 134313422020031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130020224313431 is a prime.

It is a super-2 number, since 2×130020224313431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130020224313394 and 130020224313403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130020224313439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2260956611 + ... + 2261014116.

It is an arithmetic number, because the mean of its divisors is an integer number (32506186578228).

Almost surely, 2^{130020224313431} is an apocalyptic number.

130020224313431 is a deficient number, since it is larger than the sum of its proper divisors (4521999481).

130020224313431 is an equidigital number, since it uses as much as digits as its factorization.

130020224313431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4521999480.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 130020224313431 its reverse (134313422020031), we get a palindrome (264333646333462).

The spelling of 130020224313431 in words is "one hundred thirty trillion, twenty billion, two hundred twenty-four million, three hundred thirteen thousand, four hundred thirty-one".