Base | Representation |
---|---|
bin | 111100100010111010… |
… | …0000110001001001111 |
3 | 110102121100010202201001 |
4 | 1321011310012021033 |
5 | 4112240144202224 |
6 | 135421442201131 |
7 | 12252011226025 |
oct | 1710564061117 |
9 | 412540122631 |
10 | 130020303439 |
11 | 50161087434 |
12 | 212476531a7 |
13 | c3511630c0 |
14 | 6416072715 |
15 | 35aea24544 |
hex | 1e45d0624f |
130020303439 has 4 divisors (see below), whose sum is σ = 140021865256. Its totient is φ = 120018741624.
The previous prime is 130020303419. The next prime is 130020303449. The reversal of 130020303439 is 934303020031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130020303439 - 25 = 130020303407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130020303419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000780889 + ... + 5000780914.
It is an arithmetic number, because the mean of its divisors is an integer number (35005466314).
Almost surely, 2130020303439 is an apocalyptic number.
130020303439 is a deficient number, since it is larger than the sum of its proper divisors (10001561817).
130020303439 is a wasteful number, since it uses less digits than its factorization.
130020303439 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10001561816.
The product of its (nonzero) digits is 5832, while the sum is 28.
The spelling of 130020303439 in words is "one hundred thirty billion, twenty million, three hundred three thousand, four hundred thirty-nine".
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