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13002031203300 = 223252173527240943
BaseRepresentation
bin1011110100110100010101…
…1100111000001111100100
31201000222111220120100101100
42331031011130320033210
53201011124442001200
643353014540200100
72511236311503036
oct275150534701744
951028456510340
1013002031203300
114163148719907
12155ba69b39030
13734117739369
1432d431ac3c56
1517832cb5ed00
hexbd3457383e4

13002031203300 has 216 divisors, whose sum is σ = 43163860836096. Its totient is φ = 3262316129280.

The previous prime is 13002031203233. The next prime is 13002031203341. The reversal of 13002031203300 is 330213020031.

13002031203300 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 20 + 312 + 0 + 330 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 53842629 + ... + 54083571.

It is an arithmetic number, because the mean of its divisors is an integer number (199832689056).

Almost surely, 213002031203300 is an apocalyptic number.

13002031203300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13002031203300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21581930418048).

13002031203300 is an abundant number, since it is smaller than the sum of its proper divisors (30161829632796).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002031203300 is a wasteful number, since it uses less digits than its factorization.

13002031203300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 244507 (or 244497 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 18.

Adding to 13002031203300 its reverse (330213020031), we get a palindrome (13332244223331).

The spelling of 13002031203300 in words is "thirteen trillion, two billion, thirty-one million, two hundred three thousand, three hundred".