Base | Representation |
---|---|
bin | 1011110100110100100110… |
… | …1011010111101111100010 |
3 | 1201000222200211222211201221 |
4 | 2331031021223113233202 |
5 | 3201011301120024302 |
6 | 43353025552045254 |
7 | 2511241132300441 |
oct | 275151153275742 |
9 | 51028624884657 |
10 | 13002102111202 |
11 | 416318474aa86 |
12 | 155ba8983382a |
13 | 7341293351b9 |
14 | 32d43b2a0d58 |
15 | 178333eb9937 |
hex | bd349ad7be2 |
13002102111202 has 4 divisors (see below), whose sum is σ = 19503153166806. Its totient is φ = 6501051055600.
The previous prime is 13002102111199. The next prime is 13002102111211. The reversal of 13002102111202 is 20211120120031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8994774758641 + 4007327352561 = 2999129^2 + 2001831^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3250525527799 + ... + 3250525527802.
Almost surely, 213002102111202 is an apocalyptic number.
13002102111202 is a deficient number, since it is larger than the sum of its proper divisors (6501051055604).
13002102111202 is an equidigital number, since it uses as much as digits as its factorization.
13002102111202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6501051055603.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 13002102111202 its reverse (20211120120031), we get a palindrome (33213222231233).
The spelling of 13002102111202 in words is "thirteen trillion, two billion, one hundred two million, one hundred eleven thousand, two hundred two".
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