Search a number
-
+
130021101011 = 149872624839
BaseRepresentation
bin111100100010111011…
…1001000110111010011
3110102121101122021202202
41321011313020313103
54112240400213021
6135421511233415
712252021060224
oct1710567106723
9412541567682
10130021101011
115016158168a
122124797886b
13c351382139
1464161dd24b
1535aeb30a0b
hex1e45dc8dd3

130021101011 has 4 divisors (see below), whose sum is σ = 130893726000. Its totient is φ = 129148476024.

The previous prime is 130021100971. The next prime is 130021101031. The reversal of 130021101011 is 110101120031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130021101011 - 218 = 130020838867 is a prime.

It is a super-2 number, since 2×1300211010112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130021100983 and 130021101001.

It is not an unprimeable number, because it can be changed into a prime (130021101031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 436312271 + ... + 436312568.

It is an arithmetic number, because the mean of its divisors is an integer number (32723431500).

Almost surely, 2130021101011 is an apocalyptic number.

130021101011 is a deficient number, since it is larger than the sum of its proper divisors (872624989).

130021101011 is an equidigital number, since it uses as much as digits as its factorization.

130021101011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 872624988.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 130021101011 its reverse (110101120031), we get a palindrome (240122221042).

The spelling of 130021101011 in words is "one hundred thirty billion, twenty-one million, one hundred one thousand, eleven".

Divisors: 1 149 872624839 130021101011