Base | Representation |
---|---|
bin | 11000001101111110… |
… | …01100101000111111 |
3 | 1020120010210202001121 |
4 | 30012333030220333 |
5 | 203112021211111 |
6 | 5550104451411 |
7 | 640130204320 |
oct | 140677145077 |
9 | 36503722047 |
10 | 13002132031 |
11 | 5572401269 |
12 | 262a479b67 |
13 | 12c296a265 |
14 | 8b4b62447 |
15 | 511723871 |
hex | 306fcca3f |
13002132031 has 4 divisors (see below), whose sum is σ = 14859579472. Its totient is φ = 11144684592.
The previous prime is 13002131983. The next prime is 13002132061. The reversal of 13002132031 is 13023120031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13002132031 - 211 = 13002129983 is a prime.
It is a super-4 number, since 4×130021320314 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13002131996 and 13002132014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002132061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 928723710 + ... + 928723723.
It is an arithmetic number, because the mean of its divisors is an integer number (3714894868).
Almost surely, 213002132031 is an apocalyptic number.
13002132031 is a deficient number, since it is larger than the sum of its proper divisors (1857447441).
13002132031 is an equidigital number, since it uses as much as digits as its factorization.
13002132031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1857447440.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 13002132031 its reverse (13023120031), we get a palindrome (26025252062).
The spelling of 13002132031 in words is "thirteen billion, two million, one hundred thirty-two thousand, thirty-one".
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