1300213333 has 4 divisors (see below), whose sum is σ = 1300366188. Its totient is φ = 1300060480.

The previous prime is 1300213303. The next prime is 1300213349. The reversal of 1300213333 is 3333120031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1151787844 + 148425489 = 33938^2 + 12183^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300213333 - 2¹⁷ = 1300082261 is a prime.

It is a super-2 number, since 2×1300213333² = 3381109422621937778, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300213333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300213303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62866 + ... + 80947.

It is an arithmetic number, because the mean of its divisors is an integer number (325091547).

Almost surely, 2^1300213333 is an apocalyptic number.

It is an amenable number.

1300213333 is a deficient number, since it is larger than the sum of its proper divisors (152855).

1300213333 is an equidigital number, since it uses as much as digits as its factorization.

1300213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152854.

The product of its (nonzero) digits is 486, while the sum is 19.

The square root of 1300213333 is about 36058.4710297040. The cubic root of 1300213333 is about 1091.4525798260.

Adding to 1300213333 its reverse (3333120031), we get a palindrome (4633333364).

It can be divided in two parts, 13002 and 13333, that added together give a triangular number (26335 = T₂₂₉).

The spelling of 1300213333 in words is "one billion, three hundred million, two hundred thirteen thousand, three hundred thirty-three".