1300220220031 has 4 divisors (see below), whose sum is σ = 1300223636712. Its totient is φ = 1300216803352.

The previous prime is 1300220219941. The next prime is 1300220220041.

1300220220031 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300220220031 - 2¹⁹ = 1300219695743 is a prime.

It is a super-2 number, since 2×1300220220031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300220219987 and 1300220220014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300220220041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1053961 + ... + 1926466.

It is an arithmetic number, because the mean of its divisors is an integer number (325055909178).

Almost surely, 2^{1300220220031} is an apocalyptic number.

1300220220031 is a deficient number, since it is larger than the sum of its proper divisors (3416681).

1300220220031 is an equidigital number, since it uses as much as digits as its factorization.

1300220220031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3416680.

The product of its (nonzero) digits is 144, while the sum is 16.

It can be divided in two parts, 1300220 and 220031, that added together give a palindrome (1520251).

The spelling of 1300220220031 in words is "one trillion, three hundred billion, two hundred twenty million, two hundred twenty thousand, thirty-one".