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130022141111 = 317410164483
BaseRepresentation
bin111100100010111101…
…1000110110010110111
3110102121110121010111222
41321011323012302313
54112241132003421
6135421545420555
712252032651462
oct1710573066267
9412543533458
10130022141111
1150162122075
122124819a75b
13c351657695
1464163d02d9
1535aec88cab
hex1e45ec6cb7

130022141111 has 4 divisors (see below), whose sum is σ = 130432305912. Its totient is φ = 129611976312.

The previous prime is 130022141107. The next prime is 130022141129. The reversal of 130022141111 is 111141220031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130022141111 - 22 = 130022141107 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130022141111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130022141611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205081925 + ... + 205082558.

It is an arithmetic number, because the mean of its divisors is an integer number (32608076478).

Almost surely, 2130022141111 is an apocalyptic number.

130022141111 is a deficient number, since it is larger than the sum of its proper divisors (410164801).

130022141111 is an equidigital number, since it uses as much as digits as its factorization.

130022141111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 410164800.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 130022141111 its reverse (111141220031), we get a palindrome (241163361142).

The spelling of 130022141111 in words is "one hundred thirty billion, twenty-two million, one hundred forty-one thousand, one hundred eleven".

Divisors: 1 317 410164483 130022141111