Base | Representation |
---|---|
bin | 1011110100110101000111… |
… | …1110011111011111011011 |
3 | 1201001000001112222110200001 |
4 | 2331031101332133133123 |
5 | 3201012042240411103 |
6 | 43353051444153431 |
7 | 2511244442603416 |
oct | 275152176373733 |
9 | 51030045873601 |
10 | 13002241341403 |
11 | 41632462a6766 |
12 | 155bb08398877 |
13 | 73414c133032 |
14 | 32d451984b7d |
15 | 17834131d01d |
hex | bd351f9f7db |
13002241341403 has 4 divisors (see below), whose sum is σ = 13002269757160. Its totient is φ = 13002212925648.
The previous prime is 13002241341391. The next prime is 13002241341421. The reversal of 13002241341403 is 30414314220031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13002241341403 - 217 = 13002241210331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13002241341203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13510098 + ... + 14440471.
It is an arithmetic number, because the mean of its divisors is an integer number (3250567439290).
Almost surely, 213002241341403 is an apocalyptic number.
13002241341403 is a deficient number, since it is larger than the sum of its proper divisors (28415757).
13002241341403 is an equidigital number, since it uses as much as digits as its factorization.
13002241341403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28415756.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13002241341403 its reverse (30414314220031), we get a palindrome (43416555561434).
The spelling of 13002241341403 in words is "thirteen trillion, two billion, two hundred forty-one million, three hundred forty-one thousand, four hundred three".
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