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13002244031 = 7349997583
BaseRepresentation
bin11000001101111111…
…00111111110111111
31020120011000102200202
430012333213332333
5203112033302111
65550111114115
7640131152000
oct140677477677
936504012622
1013002244031
115572478427
12262a51293b
1312c29a922a
148b4b911a7
15511746b3b
hex306fe7fbf

13002244031 has 16 divisors (see below), whose sum is σ = 15168000000. Its totient is φ = 11141081784.

The previous prime is 13002244009. The next prime is 13002244039. The reversal of 13002244031 is 13044220031.

It is not a de Polignac number, because 13002244031 - 230 = 11928502207 is a prime.

It is a super-2 number, since 2×130022440312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13002243994 and 13002244012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002244039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1710866 + ... + 1718448.

It is an arithmetic number, because the mean of its divisors is an integer number (948000000).

Almost surely, 213002244031 is an apocalyptic number.

13002244031 is a deficient number, since it is larger than the sum of its proper divisors (2165755969).

13002244031 is an frugal number, since it uses more digits than its factorization.

13002244031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12603 (or 12589 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13002244031 its reverse (13044220031), we get a palindrome (26046464062).

The spelling of 13002244031 in words is "thirteen billion, two million, two hundred forty-four thousand, thirty-one".

Divisors: 1 7 49 343 4999 7583 34993 53081 244951 371567 1714657 2600969 37907417 265351919 1857463433 13002244031