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13002311114 = 213500088889
BaseRepresentation
bin11000001101111111…
…11000010111001010
31020120011010211201022
430012333320113022
5203112042423424
65550112352442
7640131551402
oct140677702712
936504124638
1013002311114
115572513871
12262a545722
1312c2a00920
148b4bab802
1551175b95e
hex306ff85ca

13002311114 has 8 divisors (see below), whose sum is σ = 21003733380. Its totient is φ = 6001066656.

The previous prime is 13002311089. The next prime is 13002311131. The reversal of 13002311114 is 41111320031.

It can be written as a sum of positive squares in 2 ways, for example, as 12450765889 + 551545225 = 111583^2 + 23485^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13002311092 and 13002311101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250044419 + ... + 250044470.

Almost surely, 213002311114 is an apocalyptic number.

13002311114 is a deficient number, since it is larger than the sum of its proper divisors (8001422266).

13002311114 is a wasteful number, since it uses less digits than its factorization.

13002311114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 500088904.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13002311114 its reverse (41111320031), we get a palindrome (54113631145).

The spelling of 13002311114 in words is "thirteen billion, two million, three hundred eleven thousand, one hundred fourteen".

Divisors: 1 2 13 26 500088889 1000177778 6501155557 13002311114