Base | Representation |
---|---|
bin | 1011110100110101011000… |
… | …1001011100100110010000 |
3 | 1201001000020102122212000000 |
4 | 2331031112021130212100 |
5 | 3201012213144301000 |
6 | 43353102424130000 |
7 | 2511246252456450 |
oct | 275152611344620 |
9 | 51030212585000 |
10 | 13002311322000 |
11 | 4163281854170 |
12 | 155bb27906900 |
13 | 734160795a80 |
14 | 32d45ad9dd60 |
15 | 178347543000 |
hex | bd35625c990 |
13002311322000 has 4480 divisors, whose sum is σ = 64788893245440. Its totient is φ = 2435443200000.
The previous prime is 13002311321977. The next prime is 13002311322029. The reversal of 13002311322000 is 22311320031.
13002311322000 is a `hidden beast` number, since 1 + 30 + 0 + 2 + 311 + 322 + 0 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 895 ways as a sum of consecutive naturals, for example, 86108021925 + ... + 86108022075.
It is an arithmetic number, because the mean of its divisors is an integer number (14461806528).
Almost surely, 213002311322000 is an apocalyptic number.
13002311322000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13002311322000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32394446622720).
13002311322000 is an abundant number, since it is smaller than the sum of its proper divisors (51786581923440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13002311322000 is a wasteful number, since it uses less digits than its factorization.
13002311322000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282 (or 251 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13002311322000 its reverse (22311320031), we get a palindrome (13024622642031).
The spelling of 13002311322000 in words is "thirteen trillion, two billion, three hundred eleven million, three hundred twenty-two thousand".
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