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130024111023 = 3217849830791
BaseRepresentation
bin111100100011000001…
…0100111101110101111
3110102121121022012201200
41321012002213232233
54112242133023043
6135422055540543
712252055464612
oct1710602475657
9412547265650
10130024111023
11501632480a4
122124898a753
13c351b97201
146416784179
1535b00277d3
hex1e460a7baf

130024111023 has 12 divisors (see below), whose sum is σ = 198860405328. Its totient is φ = 81583755840.

The previous prime is 130024111013. The next prime is 130024111027. The reversal of 130024111023 is 320111420031.

It is not a de Polignac number, because 130024111023 - 28 = 130024110767 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130024110987 and 130024111005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130024111027) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 424915243 + ... + 424915548.

It is an arithmetic number, because the mean of its divisors is an integer number (16571700444).

Almost surely, 2130024111023 is an apocalyptic number.

130024111023 is a deficient number, since it is larger than the sum of its proper divisors (68836294305).

130024111023 is a wasteful number, since it uses less digits than its factorization.

130024111023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 849830814 (or 849830811 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 130024111023 its reverse (320111420031), we get a palindrome (450135531054).

The spelling of 130024111023 in words is "one hundred thirty billion, twenty-four million, one hundred eleven thousand, twenty-three".

Divisors: 1 3 9 17 51 153 849830791 2549492373 7648477119 14447123447 43341370341 130024111023