Base | Representation |
---|---|
bin | 10010111010111100011… |
… | …010100101101010111010 |
3 | 11121022011001020012012102 |
4 | 102322330122211222322 |
5 | 132300343222210132 |
6 | 2433153401343402 |
7 | 162640121633555 |
oct | 22727432455272 |
9 | 4538131205172 |
10 | 1300241210042 |
11 | 46147a2a1935 |
12 | 18bbb4197b62 |
13 | 957c607cc88 |
14 | 46d0961769c |
15 | 23c501bec62 |
hex | 12ebc6a5aba |
1300241210042 has 8 divisors (see below), whose sum is σ = 1958953718016. Its totient is φ = 647256637372.
The previous prime is 1300241210033. The next prime is 1300241210101. The reversal of 1300241210042 is 2400121420031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1300241209996 and 1300241210023.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1431983258 + ... + 1431984165.
It is an arithmetic number, because the mean of its divisors is an integer number (244869214752).
Almost surely, 21300241210042 is an apocalyptic number.
1300241210042 is a deficient number, since it is larger than the sum of its proper divisors (658712507974).
1300241210042 is a wasteful number, since it uses less digits than its factorization.
1300241210042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2863967652.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1300241210042 its reverse (2400121420031), we get a palindrome (3700362630073).
The spelling of 1300241210042 in words is "one trillion, three hundred billion, two hundred forty-one million, two hundred ten thousand, forty-two".
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