Base | Representation |
---|---|
bin | 10010111010111100011… |
… | …010101000100110000101 |
3 | 11121022011001020210122002 |
4 | 102322330122220212011 |
5 | 132300343223101041 |
6 | 2433153401515045 |
7 | 162640122013520 |
oct | 22727432504605 |
9 | 4538131223562 |
10 | 1300241222021 |
11 | 46147a2aa935 |
12 | 18bbb41a2a85 |
13 | 957c6085571 |
14 | 46d0961bbb7 |
15 | 23c501c359b |
hex | 12ebc6a8985 |
1300241222021 has 8 divisors (see below), whose sum is σ = 1486336953024. Its totient is φ = 1114232237280.
The previous prime is 1300241221991. The next prime is 1300241222023. The reversal of 1300241222021 is 1202221420031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1300241222021 - 210 = 1300241220997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300241221984 and 1300241222002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300241222023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21654440 + ... + 21714401.
It is an arithmetic number, because the mean of its divisors is an integer number (185792119128).
Almost surely, 21300241222021 is an apocalyptic number.
It is an amenable number.
1300241222021 is a deficient number, since it is larger than the sum of its proper divisors (186095731003).
1300241222021 is an equidigital number, since it uses as much as digits as its factorization.
1300241222021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43373131.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1300241222021 its reverse (1202221420031), we get a palindrome (2502462642052).
The spelling of 1300241222021 in words is "one trillion, three hundred billion, two hundred forty-one million, two hundred twenty-two thousand, twenty-one".
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