Base | Representation |
---|---|
bin | 10010111010111100100… |
… | …110001001101100110001 |
3 | 11121022011020221012011120 |
4 | 102322330212021230301 |
5 | 132300400011204301 |
6 | 2433153550332453 |
7 | 162640156460013 |
oct | 22727446115461 |
9 | 4538136835146 |
10 | 1300244241201 |
11 | 461480a82224 |
12 | 18bbb51ba129 |
13 | 957c68a1869 |
14 | 46d09ba61b3 |
15 | 23c505bce36 |
hex | 12ebc989b31 |
1300244241201 has 4 divisors (see below), whose sum is σ = 1733658988272. Its totient is φ = 866829494132.
The previous prime is 1300244241097. The next prime is 1300244241203. The reversal of 1300244241201 is 1021424420031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1300244241201 - 218 = 1300243979057 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1300244241203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216707373531 + ... + 216707373536.
It is an arithmetic number, because the mean of its divisors is an integer number (433414747068).
Almost surely, 21300244241201 is an apocalyptic number.
It is an amenable number.
1300244241201 is a deficient number, since it is larger than the sum of its proper divisors (433414747071).
1300244241201 is an equidigital number, since it uses as much as digits as its factorization.
1300244241201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433414747070.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1300244241201 its reverse (1021424420031), we get a palindrome (2321668661232).
The spelling of 1300244241201 in words is "one trillion, three hundred billion, two hundred forty-four million, two hundred forty-one thousand, two hundred one".
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