Base | Representation |
---|---|
bin | 10010111010111111111… |
… | …011000001000100111010 |
3 | 11121022022010221012020100 |
4 | 102322333323001010322 |
5 | 132301003302330204 |
6 | 2433203302340230 |
7 | 162641434666122 |
oct | 22727773010472 |
9 | 4538263835210 |
10 | 1300300042554 |
11 | 4614aa525647 |
12 | 19000ba2a676 |
13 | 9580530b706 |
14 | 46d1336dc82 |
15 | 23c55441a39 |
hex | 12ebfec113a |
1300300042554 has 12 divisors (see below), whose sum is σ = 2817316758906. Its totient is φ = 433433347512.
The previous prime is 1300300042463. The next prime is 1300300042567. The reversal of 1300300042554 is 4552400030031.
1300300042554 is a `hidden beast` number, since 1 + 300 + 300 + 0 + 4 + 2 + 5 + 54 = 666.
It can be written as a sum of positive squares in only one way, i.e., 1300222514529 + 77528025 = 1140273^2 + 8805^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 36119445609 + ... + 36119445644.
Almost surely, 21300300042554 is an apocalyptic number.
1300300042554 is an abundant number, since it is smaller than the sum of its proper divisors (1517016716352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300300042554 is a wasteful number, since it uses less digits than its factorization.
1300300042554 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72238891261 (or 72238891258 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 27.
Adding to 1300300042554 its reverse (4552400030031), we get a palindrome (5852700072585).
The spelling of 1300300042554 in words is "one trillion, three hundred billion, three hundred million, forty-two thousand, five hundred fifty-four".
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